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Home » V_k = \frac13 \pi (kr)^2 (2kr) = \frac13 \pi k^2 r^2 \cdot 2kr = \frac23 \pi k^3 r^3 - AMAZONAWS

V_k = \frac13 \pi (kr)^2 (2kr) = \frac13 \pi k^2 r^2 \cdot 2kr = \frac23 \pi k^3 r^3 - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
V_k = \frac{1}{3} \pi (kr)^2 (2kr) = \frac{1}{3} \pi k^2 r^2 \cdot 2kr = \frac{2}{3} \pi k^3 r^3

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📌 \frac{\sqrt{3} + 1}{\sqrt{3} - 1} \cdot \frac{\sqrt{3} + 1}{\sqrt{3} + 1} = \frac{(\sqrt{3} + 1)^2}{(\sqrt{3})^2 - (1)^2} = \frac{3 + 2\sqrt{3} + 1}{3 - 1} = \frac{4 + 2\sqrt{3}}{2} = 2 + \sqrt{3}.

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