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Home » \tan 75^\circ = \frac{1 + \frac1{\sqrt3}}{1 - 1 \cdot \frac1{\sqrt3}} = \frac{\frac{\sqrt3 + 1}{\sqrt3}}{\frac{\sqrt3 - 1}{\sqrt3}} = \frac{\sqrt3 + 1}{\sqrt3 - 1}. - AMAZONAWS

\tan 75^\circ = \frac{1 + \frac1{\sqrt3}}{1 - 1 \cdot \frac1{\sqrt3}} = \frac{\frac{\sqrt3 + 1}{\sqrt3}}{\frac{\sqrt3 - 1}{\sqrt3}} = \frac{\sqrt3 + 1}{\sqrt3 - 1}. - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
\tan 75^\circ = \frac{1 + \frac{1}{\sqrt{3}}}{1 - 1 \cdot \frac{1}{\sqrt{3}}} = \frac{\frac{\sqrt{3} + 1}{\sqrt{3}}}{\frac{\sqrt{3} - 1}{\sqrt{3}}} = \frac{\sqrt{3} + 1}{\sqrt{3} - 1}.

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