A_{\textwalkway} = \frac12 \pi (5r)^2 = \frac12 \pi \times 25r^2 = \frac252 \pi r^2 - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$A_{\text{walkway}} = \frac{1}{2} \pi (5r)^2 = \frac{1}{2} \pi \times 25r^2 = \frac{25}{2} \pi r^2$