WEBVTT

NOTE RF Effects in Real Components

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<v Narrator>Skin effect.

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<v Pool>Question. What is the result of conductor skin effect?

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<v Pool>Answer. Resistance increases as frequency increases because RF current flows closer to the surface.

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<v Narrator>At DC, current uses the whole cross-section. At RF, induced eddy currents push it outward until it flows only in a thin surface layer, so the effective cross-section shrinks and resistance rises with frequency.

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<v Narrator>Three consequences worth carrying: Flat strap beats round wire for RF bonding, because what matters is surface perimeter rather than cross-sectional area. That is the Technician station-setup answer, now with its reason.

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<v Narrator>Silver plating helps at RF and not at DC, only the surface carries current, so only the surface's conductivity matters.

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<v Narrator>Hollow tubing is as good as solid rod at RF and much lighter, which is why beam elements and amplifier tank coils are tubing.

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<v Pool>Question. What is the primary cause of loss in film capacitors at RF?

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<v Pool>Answer. Skin effect.

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<v Narrator>Everything has parasitics.

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<v Pool>Question. What combines to create the self-resonance of a component?

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<v Pool>Answer. The component's nominal and parasitic reactance.

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<v Narrator>Every real component is the thing it is supposed to be plus a small amount of the thing it is not.

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<v Narrator>Those parasitics resonate against the nominal value, and above that self-resonant frequency the component behaves as its parasitic instead.

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<v Pool>Question. What parasitic characteristic creates an inductor's self-resonance?

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<v Pool>Answer. Inter-turn capacitance.

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<v Narrator>Capacitance between adjacent turns. Above self-resonance the inductor is capacitive, the General components lesson stated that result; this is the mechanism.

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<v Pool>Question. What parasitic characteristic causes electrolytic capacitors to be unsuitable for use at RF?

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<v Pool>Answer. Inductance.

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<v Narrator>An electrolytic is a long strip of foil rolled up, which is a coil. Its series inductance means it stops being a capacitor at a few hundred kilohertz.

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<v Narrator>This is why a power supply needs both a large electrolytic for bulk smoothing and a small ceramic in parallel for RF bypass: neither works over the whole range.

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<v Pool>Question. Why is it important to keep lead lengths short for components used in circuits for VHF and above?

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<v Pool>Answer. To minimize inductive reactance.

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<v Narrator>A wire's inductance is roughly 20 nH per inch. At 145 MHz that is about 18 ohms per inch of lead, comparable with the impedances in the circuit, so lead length is a circuit element whether you intended it or not.

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<v Narrator>Electrical length.

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<v Pool>Question. Why are short connections used at microwave frequencies?

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<v Pool>Answer. To reduce phase shift along the connection.

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<v Narrator>At microwave a connection is a transmission line, and its length is a meaningful fraction of a wavelength. A signal arrives phase-shifted, which changes what the circuit does.

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<v Pool>Question. As a conductor's diameter increases, what is the effect on its electrical length?

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<v Pool>Answer. It increases.

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<v Narrator>A fatter conductor is electrically longer than a thin one of the same physical length, because increased capacitance to its surroundings slows the wave.

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<v Narrator>This is why a fat dipole is cut shorter than a thin-wire one for the same frequency, the same end effect that gives 468 rather than 492 in the dipole formula. Real and reactive power.

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<v Pool>Question. What is reactive power?

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<v Pool>Answer. Wattless, nonproductive power.

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<v Pool>Question. What happens to reactive power in ideal inductors and capacitors?

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<v Pool>Answer. Energy is stored in magnetic or electric fields, but power is not dissipated.

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<v Pool>Question. What is the phase relationship between current and voltage for reactive power?

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<v Pool>Answer. They are 90 degrees out of phase.

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<v Narrator>Reactive power flows into a reactance and back out again each cycle. Nothing is consumed, the current is real and does real work in the wire's resistance, but the reactance itself dissipates nothing.

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<v Narrator>The quantitative consequence:

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<v Pool>Question. How much real power is consumed in a circuit consisting of a 100-ohm resistor in series with a 100-ohm inductive reactance drawing 1 ampere?

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<v Pool>Answer. 100 watts.

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<v Narrator>P = I to the power of 2R = 1 to the power of 2 times 100 = 100 watts. The reactance contributes nothing to real power, even though it contributes to impedance and therefore to how much current flows for a given voltage.

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<v Narrator>That is why power in a reactive circuit is P = E times I times cos(θ), and why the foundations power lesson flagged the qualifier.

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<v Narrator>Here only the resistance dissipates, and I to the power of 2R with the resistive part alone is the whole answer. Check yourself. Why is silver plating useful on an RF coil and pointless on a DC busbar?

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<v Narrator>Your bypass capacitor is a 10 µF electrolytic and the circuit still has RF on the supply rail. What is wrong? A circuit draws 2 A through 50 Ω of resistance in series with 200 Ω of reactance. Real power?

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<v Narrator>Skin effect, at RF the current flows only in the surface layer, so surface conductivity is what matters. At DC the whole cross-section conducts.

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<v Narrator>An electrolytic's series inductance makes it useless above a few hundred kilohertz. Add a small ceramic in parallel. P = I to the power of 2R using the resistance only: 4 times 50 = 200 watts.

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<v Narrator>The reactance dissipates nothing.
