We aim to maximize one of $6a$, $6b$, or $6c$. Without loss of generality, let’s maximize $6a$. This implies maximizing $a$ subject to $a + b + c = 14$ and $\gcd(a, b, c) = 1$. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$We aim to maximize one of $6a$, $6b$, or $6c$. Without loss of generality, let’s maximize $6a$. This implies maximizing $a$ subject to $a + b + c = 14$ and $\gcd(a, b, c) = 1$.$

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