a_n = \sum_k=1^n \frackn - \frac13 \sum_k=1^n \left( \frackn \right)^3 - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$a_n = \sum_{k=1}^{n} \frac{k}{n} - \frac{1}{3} \sum_{k=1}^{n} \left( \frac{k}{n} \right)^3$