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Home » z = 30^\circ, 60^\circ, 210^\circ, 240^\circ - AMAZONAWS

z = 30^\circ, 60^\circ, 210^\circ, 240^\circ - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$z = 30^\circ, 60^\circ, 210^\circ, 240^\circ$

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\[ C'(t) = \frac{-kt^2 + k}{(t^2 + 1)^2} \]
The numerator must be zero:

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Divide by 2 to find \(z\):

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