Solution:** Since $\mathbfx + \mathbfy + \mathbfz = \mathbf0$, then $\mathbfz = -(\mathbfx + \mathbfy)$. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$Solution:** Since $\mathbf{x} + \mathbf{y} + \mathbf{z} = \mathbf{0}$, then $\mathbf{z} = -(\mathbf{x} + \mathbf{y})$.$