\binom103 = \frac10!3!(10-3)! = \frac10 \times 9 \times 8 \times 7!3! \times 7! = \frac10 \times 9 \times 83 \times 2 \times 1 = \frac7206 = 120 - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$\binom{10}{3} = \frac{10!}{3!(10-3)!} = \frac{10 \times 9 \times 8 \times 7!}{3! \times 7!} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = \frac{720}{6} = 120$

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