$ P(7) = \binom77 (0.4)^7 (0.6)^0 = 1 \cdot 0.0016384 \cdot 1 = 0.0016384 $ - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$P(7) = \binom{7}{7} (0.4)^7 (0.6)^0 = 1 \cdot 0.0016384 \cdot 1 = 0.0016384$