$ P(1) = \binom61 (0.3)^1 (0.7)^5 = 6 \cdot 0.3 \cdot 0.16807 = 0.302526 $ - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$P(1) = \binom{6}{1} (0.3)^1 (0.7)^5 = 6 \cdot 0.3 \cdot 0.16807 = 0.302526$