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Home » \[ C'(t) = \frack(1 - t^2)(t^2 + 1)^2 \] - AMAZONAWS

\[ C'(t) = \frack(1 - t^2)(t^2 + 1)^2 \] - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
\[ C'(t) = \frac{k(1 - t^2)}{(t^2 + 1)^2} \]

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  • \[ a = \frac{1}{2} \]
  • \frac{6}{3} \geq \frac{3}{\frac{1}{x} + \frac{1}{y} + \frac{1}{z}}
  • \frac{1}{x} + \frac{1}{y} + \frac{1}{z} \geq \frac{3}{2}

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