For $z = 90^\circ$, $\sin(180^\circ) = 0$ and $\cos(90^\circ) = 0$, so it satisfies. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$For $z = 90^\circ$, $\sin(180^\circ) = 0$ and $\cos(90^\circ) = 0$, so it satisfies.$