For $z = 270^\circ$, $\sin(540^\circ) = 0$ and $\cos(270^\circ) = 0$, so it satisfies. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$For $z = 270^\circ$, $\sin(540^\circ) = 0$ and $\cos(270^\circ) = 0$, so it satisfies.$