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Home » Solution: Let $a + b = 2024$, and suppose $d = \gcd(a,b)$. Since $d \mid a$ and $d \mid b$, then $d \mid (a + b) = 2024$. So $d$ is a divisor of $2024$. - AMAZONAWS

Solution: Let $a + b = 2024$, and suppose $d = \gcd(a,b)$. Since $d \mid a$ and $d \mid b$, then $d \mid (a + b) = 2024$. So $d$ is a divisor of $2024$. - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
Solution: Let $a + b = 2024$, and suppose $d = \gcd(a,b)$. Since $d \mid a$ and $d \mid b$, then $d \mid (a + b) = 2024$. So $d$ is a divisor of $2024$.

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