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Home » \mathbfa \cdot \mathbfa = 1^2 + 1^2 + 1^2 = 3 - AMAZONAWS

\mathbfa \cdot \mathbfa = 1^2 + 1^2 + 1^2 = 3 - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$\mathbf{a} \cdot \mathbf{a} = 1^2 + 1^2 + 1^2 = 3$

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Final answer: \(\boxed{(x - 2y)(x + 2y)(x^2 + 4y^2)}\)
4p + 2q = -12 \quad \text{(Equation 7)}

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