From $ -y = x $ and $ x = y $, substituting: $ -x = x \Rightarrow x = 0 $, then $ y = 0 $. Only solution is $\mathbfv = eginpmatrix 0 \ 0 \endpmatrix$, but \( \|\mathbfv\|^2 = 0 - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$From $ -y = x $ and $ x = y $, substituting: $ -x = x \Rightarrow x = 0 $, then $ y = 0 $. Only solution is $\mathbf{v} = egin{pmatrix} 0 \ 0 \end{pmatrix}$, but \( \|\mathbf{v}\|^2 = 0$

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