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Home » \( rac-\sqrt5+1-\sqrt5-1 = rac\sqrt5-1\sqrt5+1 = rac(\sqrt5-1)^25 - 1 = rac6 - 2\sqrt54 \), but we earlier derived it correctly as \( rac3 - \sqrt52 \), so it checks. - AMAZONAWS

\( rac-\sqrt5+1-\sqrt5-1 = rac\sqrt5-1\sqrt5+1 = rac(\sqrt5-1)^25 - 1 = rac6 - 2\sqrt54 \), but we earlier derived it correctly as \( rac3 - \sqrt52 \), so it checks. - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
\( rac{-\sqrt{5}+1}{-\sqrt{5}-1} = rac{\sqrt{5}-1}{\sqrt{5}+1} = rac{(\sqrt{5}-1)^2}{5 - 1} = rac{6 - 2\sqrt{5}}{4} \), but we earlier derived it correctly as \( rac{3 - \sqrt{5}}{2} \), so it checks.

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