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Home » -4y^2 + 12y + 1 \geq 0 - AMAZONAWS

-4y^2 + 12y + 1 \geq 0 - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$-4y^2 + 12y + 1 \geq 0$

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Therefore, the largest possible value is $oxed{1012}$.
2(r+1) = (3 - \sqrt{5})(r - 1)
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