For $x$ and $y$ to be integers, $a$ and $b$ must both be even (since if both were odd, $ab$ would be odd; if one odd and one even, $a + b$ is odd). So both $a$ and $b$ must be even. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$For $x$ and $y$ to be integers, $a$ and $b$ must both be even (since if both were odd, $ab$ would be odd; if one odd and one even, $a + b$ is odd). So both $a$ and $b$ must be even.$

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