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Home » z = e^i(\pi + 2k\pi)/4 = e^i\pi(2k+1)/4, \quad k = 0, 1, 2, 3 - AMAZONAWS

z = e^i(\pi + 2k\pi)/4 = e^i\pi(2k+1)/4, \quad k = 0, 1, 2, 3 - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
z = e^{i(\pi + 2k\pi)/4} = e^{i\pi(2k+1)/4}, \quad k = 0, 1, 2, 3

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