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Home » -16((y - 2)^2 - 4) = -16(y - 2)^2 + 64 - AMAZONAWS

-16((y - 2)^2 - 4) = -16(y - 2)^2 + 64 - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

-16((y - 2)^2 - 4) = -16(y - 2)^2 + 64

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= 3 \cdot 512 - 3 \cdot 1 + 0 = 1536 - 3 = 1533
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y^2 - 4y = (y - 2)^2 - 4
Using the identity $ \mathbf{a} \times (\mathbf{v} \times \mathbf{a})...
with $ a_1 = 2 $ (E, J), $ a_2 = 3 $ (EE, EJ, JE) — JJ is invalid.
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