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Home » This implies $ n^2 - 1 \equiv 0 \pmod12 $, or $ (n - 1)(n + 1) \equiv 0 \pmod12 $. - AMAZONAWS

This implies $ n^2 - 1 \equiv 0 \pmod12 $, or $ (n - 1)(n + 1) \equiv 0 \pmod12 $. - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
This implies $ n^2 - 1 \equiv 0 \pmod{12} $, or $ (n - 1)(n + 1) \equiv 0 \pmod{12} $.

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