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Home Β» t = \frac-b \pm \sqrtb^2 - 4ac2a = \frac5 \pm \sqrt25 - 242 = \frac5 \pm 12 - AMAZONAWS

t = \frac-b \pm \sqrtb^2 - 4ac2a = \frac5 \pm \sqrt25 - 242 = \frac5 \pm 12 - AMAZONAWS

πŸ“… March 6, 2026 πŸ‘€ scraface
Mar 06, 2026
t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{5 \pm \sqrt{25 - 24}}{2} = \frac{5 \pm 1}{2}

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