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Home » Für $ x \in \mathbbZ \setminus \0, \pm1\ $: Wähle $ y = x $. Dann $ x \mid y $ ist wahr. Aber $ y \mid x $ ⇒ $ x \mid x $: wahr, aber hier ist die Implikation: - AMAZONAWS

Für $ x \in \mathbbZ \setminus \0, \pm1\ $: Wähle $ y = x $. Dann $ x \mid y $ ist wahr. Aber $ y \mid x $ ⇒ $ x \mid x $: wahr, aber hier ist die Implikation: - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
Für $ x \in \mathbb{Z} \setminus \{0, \pm1\} $: Wähle $ y = x $. Dann $ x \mid y $ ist wahr. Aber $ y \mid x $ ⇒ $ x \mid x $: wahr, aber hier ist die Implikation:

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