As $ t \to \infty $, the term $ e^-0.1(t-5) \to 0 $. Thus, the denominator approaches 1: - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$As $ t \to \infty $, the term $ e^{-0.1(t-5)} \to 0 $. Thus, the denominator approaches 1:$