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Home » Let’s compute the reduction of $ (y + 1)^2025 $ modulo $ y^2 + y + 1 $. Let’s denote $ \omega $ as a primitive cube root of unity (so $ \omega^3 = 1 $, $ \omega - AMAZONAWS

Let’s compute the reduction of $ (y + 1)^2025 $ modulo $ y^2 + y + 1 $. Let’s denote $ \omega $ as a primitive cube root of unity (so $ \omega^3 = 1 $, $ \omega - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
Let’s compute the reduction of $ (y + 1)^{2025} $ modulo $ y^2 + y + 1 $. Let’s denote $ \omega $ as a primitive cube root of unity (so $ \omega^3 = 1 $, $ \omega

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