Let $P = \mathbfr(t)$. The vector $\overrightarrowCP = \mathbfr(t) - \mathbfC = \langle 1 + 3t - 2, 3 - 2t + 1, -2 + 3t - 3 - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$Let $P = \mathbf{r}(t)$. The vector $\overrightarrow{CP} = \mathbf{r}(t) - \mathbf{C} = \langle 1 + 3t - 2, 3 - 2t + 1, -2 + 3t - 3$