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Home » e 1 $, and $ \omega^2 + \omega + 1 = 0 $), and note that this polynomial divides $ y^2 + y + 1 $. - AMAZONAWS

e 1 $, and $ \omega^2 + \omega + 1 = 0 $), and note that this polynomial divides $ y^2 + y + 1 $. - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
e 1 $, and $ \omega^2 + \omega + 1 = 0 $), and note that this polynomial divides $ y^2 + y + 1 $.

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