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Home » A^2 - 16BC = (A - 4\sqrtBC)(A + 4\sqrtBC) - AMAZONAWS

A^2 - 16BC = (A - 4\sqrtBC)(A + 4\sqrtBC) - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$A^2 - 16BC = (A - 4\sqrt{BC})(A + 4\sqrt{BC})$

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