Since $ p(1) = 0 $, $ x = 1 $ is indeed a root. To check the multiplicity, we compute the derivative $ p'(x) $: - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$Since $ p(1) = 0 $, $ x = 1 $ is indeed a root. To check the multiplicity, we compute the derivative $ p'(x) $:$