P(X = 4) = \binom64 \left(\frac12\right)^4 \left(\frac12\right)^2 = \binom64 \left(\frac12\right)^6 - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$P(X = 4) = \binom{6}{4} \left(\frac{1}{2}\right)^4 \left(\frac{1}{2}\right)^2 = \binom{6}{4} \left(\frac{1}{2}\right)^6$