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Let the distance be \(d\). - AMAZONAWS
Let the distance be \(d\). - AMAZONAWS
📅 March 6, 2026
👤 scraface
Mar 06, 2026
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📌 Then, \(x = rac{8 \pm \sqrt{16}}{4} = rac{8 \pm 4}{4}\).
📌 Solution: The diagonal of the square is the diameter of the circle. Using the Pythagorean theorem, the diagonal $ d $ of a square with side length $ 8 $ is $ d = 8\sqrt{2} $. Thus, the radius $ r $ of the circle is half the diagonal:
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📌 Solution: Let $ p(x) = ax^2 + bx + c $. Using the given values:
