Integrate term by term: \(\int 3x^2 dx = x^3\), \(\int 2x dx = x^2\), so \(\int_0^1 (3x^2 + 2x) dx = [x^3 + x^2]_0^1 = (1 + 1) - (0 + 0) = 2\). - AMAZONAWS 📅 March 6, 2026 👤 scraface Mar 06, 2026
![Integrate term by term: \(\int 3x^2 dx = x^3\), \(\int 2x dx = x^2\), so \(\int_0^1 (3x^2 + 2x) dx = [x^3 + x^2]_0^1 = (1 + 1) - (0 + 0) = 2\).](https://soloferat.biz.id/images/integrate-term-by-term-int-3x2-dx--x3-int-2x-dx--x2-so-int01-3x2--2x-dx--x3--x201--1--1---0--0--2.jpg)
