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\[ \frac60 + x200 + x = 0.5 \] - AMAZONAWS
\[ \frac60 + x200 + x = 0.5 \] - AMAZONAWS
📅 March 6, 2026
👤 scraface
Mar 06, 2026
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📌 Solution: The diagonal of the square is the diameter of the circle. Using the Pythagorean theorem, the diagonal $ d $ of a square with side length $ 8 $ is $ d = 8\sqrt{2} $. Thus, the radius $ r $ of the circle is half the diagonal:
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📌 الطول هو \(2 \times 8.33 \approx 16.67\).
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📌 \(= 8000 \times (0.988)^{10}\)
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📌 To find the time at which this maximum occurs, we use:
📌 w(t) = R\sin\left(\frac{\pi}{6}t + \phi\right)
![\[ \frac{60 + x}{200 + x} = 0.5 \]](https://soloferat.biz.id/images/-frac60--x200--x--05-.jpg)
