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x² + 2x - 140 = 0 - AMAZONAWS
x² + 2x - 140 = 0 - AMAZONAWS
📅 March 6, 2026
👤 scraface
Mar 06, 2026
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📌 But any integer $ B $ divides some multiple of 9 (e.g., take $ D = B \cdot 9 $, but again, $ B $ must be divisible by 11).
📌 But every positive integer divides some multiple of 9 (e.g., $ D = B \cdot 9 $ only if $ B \mid D $, so if we set $ D = B \cdot k $, we need $ 9 \mid Bk $. But we can choose $ k $).
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