Maximizing $d$ requires minimizing $m + n$, with $m, n \geq 1$ and $\gcd(m, n) = 1$. The minimum value of $m + n$ is 2, achieved when $m = n = 1$, which are coprime. Then: - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$Maximizing $d$ requires minimizing $m + n$, with $m, n \geq 1$ and $\gcd(m, n) = 1$. The minimum value of $m + n$ is 2, achieved when $m = n = 1$, which are coprime. Then:$

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