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Home » \fracddt(6t^2 + 4t + 30) = 12t + 4 = 0 \Rightarrow t = -\frac13 - AMAZONAWS

\fracddt(6t^2 + 4t + 30) = 12t + 4 = 0 \Rightarrow t = -\frac13 - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
\frac{d}{dt}(6t^2 + 4t + 30) = 12t + 4 = 0 \Rightarrow t = -\frac{1}{3}

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