But since $ D $ must be divisible by 9, and $ B \mid D $, $ B $ must be such that it divides at least one multiple of 9 in the range. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$But since $ D $ must be divisible by 9, and $ B \mid D $, $ B $ must be such that it divides at least one multiple of 9 in the range.$