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Home » $ P(5) = \binom75 (0.4)^5 (0.6)^2 = 21 \cdot 0.01024 \cdot 0.36 = 0.0774144 $ - AMAZONAWS

$ P(5) = \binom75 (0.4)^5 (0.6)^2 = 21 \cdot 0.01024 \cdot 0.36 = 0.0774144 $ - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
$ P(5) = \binom{7}{5} (0.4)^5 (0.6)^2 = 21 \cdot 0.01024 \cdot 0.36 = 0.0774144 $

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