\[ C'(t) = \frac(k)(t^2 + 1) - (kt)(2t)(t^2 + 1)^2 \] - AMAZONAWS 📅 March 6, 2026 👤 scraface Mar 06, 2026
![\[ C'(t) = \frac{(k)(t^2 + 1) - (kt)(2t)}{(t^2 + 1)^2} \]](https://soloferat.biz.id/images/-ct--frackt2--1---kt2tt2--12-.jpg)
