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\[ C'(t) = \frack(t^2 + 1) - 2kt^2(t^2 + 1)^2 \] - AMAZONAWS
\[ C'(t) = \frack(t^2 + 1) - 2kt^2(t^2 + 1)^2 \] - AMAZONAWS
📅 March 6, 2026
👤 scraface
Mar 06, 2026
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![\[ C'(t) = \frac{k(t^2 + 1) - 2kt^2}{(t^2 + 1)^2} \]](https://soloferat.biz.id/images/-ct--frackt2--1---2kt2t2--12-.jpg)
