To maximize $ d $, we take the largest divisor of 144 such that $ \frac144d \geq 2 $ and there exist coprime $ m, n $ with $ m + n = \frac144d $. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$To maximize $ d $, we take the largest divisor of 144 such that $ \frac{144}{d} \geq 2 $ and there exist coprime $ m, n $ with $ m + n = \frac{144}{d} $.$

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