\sum_k=1^24 3^k = 3 \cdot \frac3^24 - 13 - 1 = \frac32 (3^24 - 1) - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$\sum_{k=1}^{24} 3^k = 3 \cdot \frac{3^{24} - 1}{3 - 1} = \frac{3}{2} (3^{24} - 1)$