Solution: The equation \(\sin(2x) = \frac12\) has solutions when \(2x = \frac\pi6 + 2\pi n\) or \(2x = \frac5\pi6 + 2\pi n\) for integer \(n\). Solving for \(x\) in \([0, 2\pi]\): - AMAZONAWS 📅 March 6, 2026 👤 scraface Mar 06, 2026
![Solution: The equation \(\sin(2x) = \frac{1}{2}\) has solutions when \(2x = \frac{\pi}{6} + 2\pi n\) or \(2x = \frac{5\pi}{6} + 2\pi n\) for integer \(n\). Solving for \(x\) in \([0, 2\pi]\):](https://soloferat.biz.id/images/solution-the-equation-sin2x--frac12-has-solutions-when-2x--fracpi6--2pi-n-or-2x--frac5pi6--2pi-n-for-integer-n-solving-for-x-in-0-2pi.jpg)
