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- 12y + 4y^2 \leq y^2 - 4y + 4 - AMAZONAWS
- 12y + 4y^2 \leq y^2 - 4y + 4 - AMAZONAWS
📅 March 6, 2026
👤 scraface
Mar 06, 2026
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📌 Utiliser les propriétés des logarithmes : \( \log_2 x + \log_2 4 = \log_2 (4x) = 5 \).
