To maximize $ d $, minimize $ k + l $. Since $\gcd(k, l) = 1$, the smallest sum is 2 (when $ k = 1 $, $ l = 1 $). Then: - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$To maximize $ d $, minimize $ k + l $. Since $\gcd(k, l) = 1$, the smallest sum is 2 (when $ k = 1 $, $ l = 1 $). Then:$