This equation is in the standard form $\frac(x-h)^2a^2 - \frac(y-k)^2b^2 = 1$, where $(h, k)$ is the center. Here, $h = 0$ and $k = 0$, so the center of the hyperbola is at the origin. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$This equation is in the standard form $\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1$, where $(h, k)$ is the center. Here, $h = 0$ and $k = 0$, so the center of the hyperbola is at the origin.$

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