ight)^2 = rac12 $, $ 2x = rac\pi2 $, $ \cos^2(2x) = \cos^2(rac\pi2) = 0 $, so $ f = 0.5 + 0 = 0.5 $. - AMAZONAWS

📅 March 6, 2026 👤 scraface

Mar 06, 2026

$ight)^2 = rac{1}{2} $, $ 2x = rac{\pi}{2} $, $ \cos^2(2x) = \cos^2( rac{\pi}{2}) = 0 $, so $ f = 0.5 + 0 = 0.5 $.$