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Home » \fracV_\texttetrahedronV_\textsphere = \frac\frac\sqrt212 s^3\frac\pi \sqrt68 s^3 = \frac\sqrt212 \cdot \frac8\pi \sqrt6 = \frac2\sqrt39\pi - AMAZONAWS

\fracV_\texttetrahedronV_\textsphere = \frac\frac\sqrt212 s^3\frac\pi \sqrt68 s^3 = \frac\sqrt212 \cdot \frac8\pi \sqrt6 = \frac2\sqrt39\pi - AMAZONAWS

📅 March 6, 2026 👤 scraface
Mar 06, 2026
\frac{V_{\text{tetrahedron}}}{V_{\text{sphere}}} = \frac{\frac{\sqrt{2}}{12} s^3}{\frac{\pi \sqrt{6}}{8} s^3} = \frac{\sqrt{2}}{12} \cdot \frac{8}{\pi \sqrt{6}} = \frac{2\sqrt{3}}{9\pi}

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